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If A:B is 2:3, B:C is 4:5 and also C:D is 6:8. Discover A:B:C:D?

I to be able to find A:C , B:D.

\$fracAC = fracAB × fracBC\$

\$fracBD = fracBC × fracCD\$

But ns am no able to discover A:B:C:D.

Given,

\$A:B = 2:3\$

\$A=2x, B=3x\$

\$B:C = 4:5\$

\$B=4x, C=5x\$

Now in over two ratios in very first B has 3x value and also in second B has 4x value. Take LCM that 3x, 4x. You have 12x.

To do the value of B in an initial ratio to 12x . Multiply very first ratio v 4x and also in other ratio v 3x.

You have,

\$A:B = 8x:12x\$ and \$B:C = 12x:15x\$

On combining this two,

\$A:B:C = 8x:12x:15x\$

Now,

\$C:D = 6:8\$

\$C = 6x, D = 8x\$

Now in over two ratios in very first C has 15x value and also in second C has 6x value. Take it LCM the 15x, 6x. You have 30x.

To do the value of C in first ratio come 30x . Multiply first ratio with 2x and in various other ratio through 5x.

\$A:B:C = 16x:24x:30x\$

\$C:D = 30x:40x\$

On combining these two,

\$A:B:C:D = 16x:24x:30x:40x\$

If get rid of x.

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We have \$A:B:C:D = 16:24:30:40\$

You can also divide ratio by 2 because all terms have 2 in common.

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edited Dec 20 "16 at 16:46
reply Dec 20 "16 in ~ 16:39

Kanwaljit SinghKanwaljit singh
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