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Click below to check out ALL troubles on FinanceQuestion 175658: Please assist me settle this equation: Pat invested a total of $3,000. Component of the money yields 10 percent interestper year, and also the rest yields 8 percent attention per year. If the complete yearlyinterest indigenous this investment is $256, just how much did Pat invest at 10 percentand exactly how much in ~ 8 percent? found 2 options by jim_thompson5910, Mathtut:Answer by jim_thompson5910(35256) (Show Source): You have the right to put this solution on her website! permit x=amount invested at 10% and also y=amount invest at 8%"Pat invested a total of $3,000" translates to "Part that the money yields 10 percent interestper year, and the rest yields 8 percent attention per year. If the complete yearlyinterest from this investment is $256" translates to main point both sides by 100 to gain So we have actually the system of equations:Let"s solve by substitutionNow in order to solve this mechanism by utilizing substitution, we have to solve (or isolate) one variable. I"m going to deal with for y.So let"s isolation y in the very first equation begin with the very first equation Subtract native both political parties Rearrange the equation---------------------Since , we can now replace each in the 2nd equation through to solve for plug in right into the second equation. In various other words, replace each v . Notice we"ve eliminated the variables. So we now have a simple equation with one unknown. Distribute come Multiply incorporate like terms on the left sideSubtract 24000 indigenous both sides combine like terms on the right side divide both sides by 2 to isolation x Divide-----------------First Answer------------------------------So the first part of our answer is: because we know that we have the right to plug it into the equation (remember we previously solved for in the an initial equation).

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Begin with the equation whereby was formerly isolated. Plugin Multiply combine like state -----------------Second Answer------------------------------So the second component of our answer is: -----------------Summary------------------------------So our answers are: and also So this method that Pat invest $800 at 10% and also $2,200 at 8% price by Mathtut(3670) (Show Source): You have the right to put this systems on her website! let x and also y it is in the quantities invested at 10% and also 8%:x+y=3000........eq 1.1x+.08y=256....eq 2:rewrite eq 1 to x=3000-y and plug the value right into eq2:.1(3000-y)+.08y=256:300-.1y+.08y=256:-.02y=-44:$amount invested at 8%:$amount invested at 10%
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