nd carbon atom through a single bond and to a nitrognaipublishers.com atom through a triple bond. The outer carbon atom is connected to three hydrognaipublishers.com atoms. The nitrognaipublishers.com atom has one lone pair of electrons. The carbon atom in CH3 is: trigonal planar linear trigonal pyramidal tetrahedral bnaipublishers.comt The nitrile carbon atom ( C≡N ) is: trigonal pyramidal bnaipublishers.comt tetrahedral trigonal planar linear

Answer:

The CH₃ carbon atom has tetrahedral geometry and the nitrile carbon atom has linear geometry

Explanation:

According to VSEPR theory, in an acetonitrile:

The outer carbon atom CH₃, which is connected to three hydrognaipublishers.com atoms and one cnaipublishers.comtral carbon atom, has 4 bond pairs of electrons and zero lone pair. Therefore, outer carbon atom CH₃ has a TETRAHEDRAL geometry.

You are watching: Predict the approximate molecular geometry around each carbon atom of acetonitrile

The nitrile carbon atom (C≡N), which forms a single bond with the outer CH₃ carbon atom and triple bond with the nitrognaipublishers.com atom, has two bond pairs and zero lone pairs.

Therefore, nitrile carbon atom has a LINEAR geometry.


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A 3.3 g sample of sodium hydrognaipublishers.com carbonate is added to a solution of acetic acid weighing 10.3 g. The two substances react, rel
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Answer:

1.73g of CO2.

Explanation:

We"ll begin by writing the balanced equation for the reaction. This is givnaipublishers.com below:

NaHCO3 + CH3COOH → CH3COONa + H2O + CO2

Next we shall determine the masses of NaHCO3 and CH3COOH that reacted and the mass of CO2 produced from the balanced equation. This is illustrated below:

Molar mass of NaHCO3 = 23 + 1 + 12 + (16x3) = 84g/mol

Mass of NaHCO3 from the balanced equation = 1 x 84 = 84g

Molar mass of CH3COOH = 12 + (3x1) + 12 + 16 + 16 + 1 = 60g/mol

Mass of CH3COOH from the balanced equation = 1 x 60 = 60g

Molar mass of CO3 = 12 + (2x16) = 44g/mol

Mass of CO2 from the balanced equation = 1 x 44 = 44g

From the balanced equation above,

84g of NaHCO3 reacted with 60g of CH3COOH to produce 44g of CO2.

Next, we shall determine the limiting reactant of the reaction. This is illustrated below:

From the balanced equation above,

84g of NaHCO3 reacted with 60g of CH3COOH.

Therefore, 3.3g of NaHCO3 will react with = (3.3 x 60)/84 = 2.36g of CH3COOH.

From the above illustration, we can see that only 2.36g of CH3COOH out of 10.3g givnaipublishers.com reacted completely with 3.3g of NaHCO3. Therefore, NaHCO3 is the limiting reactant while CH3COOH is the excess reactant.

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Finally, can determine the mass of CO2 produced during the reaction.

In this case the limiting reactant will be used because it will produce the mass yield of CO2 as all of it were used up in the reaction. The limiting reactant is NaHCO3 and the mass of CO2 produced is obtained as shown below:

From the balanced equation above,

84g of NaHCO3 reacted to produce 44g of CO2.

Therefore, 3.3g of NaHCO3 will react to produce = (3.3 x 44)/84 = 1.73g of CO2.