A. F(x)=2(x+2)(x-1) B.f(x)=(x-1)2 -2 C.f(x)= (x-1)(x+3) D. F(x)=-(x+3)2 E. F(x)=-2x2-8x+3 F. F(x)=1/2x2-2

F is a reasonable function. That is denominator term is (2x2 - 2). Therefore, the domain is uncovered by setting this term same to zero.

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Domain refers to the collection of values x deserve to assume in every of this functions. Plainly x can assume all genuine values in every of the functions shown above.

As mentioned in Michael"s solution, the duty defined in F has zeros in that is denominator, which should be excluded native the domain. The functions characterized in A-E have actually no restrictions.
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